Dude this was so helpful. If my calculation are not off, 4x 250kv on 3:1 gear ratio with 6.5 inch wheels will put the vehicle thrust at about 93.65576 Pounds Vehicle Thrust.
Is there a formula to calculate how fast a vehicle will hit top speed with vehicle thrust?
Force (Newtons) = Mass (KG) * Acceleration (m/s^2)
therefore:
Force (Newtons) / Mass (KG) = Acceleration (m/s^2)
A = acceleration (m/s2)
B = the final velocity (m/s)
C = the initial velocity (m/s)
D = the time in which the change occurs (s)
E = the change in velocity (m/s)
A = ((B - C) / D) = (E / D)
therefore
(B - C) / A = D the time in which the change occurs (s)
it looks like with 2 motors, you’d hit 49-50mph, judging from where the yellow line, bottom left chart (vehicle thrust pounds, 2 motors) dips below the blue line, bottom left chart (wind drag force, pounds) (2 motors thrust force @ 50mph = 34.99lbs – wind drag force @ 50mph = 35.08lbs).
with 4 motors, it looks closer to 54mph, judging from where the red line, bottom left chart (vehicle thrust pounds, 4 motors) dips below the blue line (wind drag force, pounds).
The peak vehicle thrust of 124.88lbs (red line, bottom left chart) begins to drop off at about 25mph, because due to the increasing back emf voltage with increasing speed (red line, top left chart), sustaining 80a motor current above ~25mph would require more than the 40a battery current limit per motor.
(46v battery, 0.050ohm winding, (4) 190kv motors, 152mm tire, 42 wheel teeth, 16 motor teeth, 2.625:1 gear ratio, 100% throttle, 95% max duty cycle, 80a motor current limit & 40a battery current limit per motor)