 Just a quick question to help understand some electrical concepts:

Say I have a 12s2p battery with 30q cells. Each cell has a max continuous output of 15 amps, according to the spec sheet. How do I calculate the voltage, max current, and max power of the whole battery? How does that change if I decided to do 12s3p instead?

Thanks all

12x 3.6 = your nominal voltage (your s number multiplied by 3.6 for nominal, or 4.2 for max)

2x 15 = your max continuous amperage (change 2 to 3 for a 3p pack, change 15A to whatever max if you change cell type/model)

3000mah x 2 = your max capacity of the battery. (mah of cell multiplied by the p count)

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So let me see if I have this:

12s2p max continuous current = 30 amps max power (ignoring esc and motor limits) = 30 x 12 x 3.6 = 1296 watts nominal or 30 x 12 x 4.2 = 1512 watts at full charge (not really real-world possible)

12s3p max continuous current = 45 amps max power nominal = 45 x 12 x 3.6 = 1944 watts or 45 x 12 x 4.2 = 2268 watts full-charge max

Is that correct? Does that mean that adding additional cells in parallel (increasing p number) always increases the battery’s maximum output current?

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bingo, you got it.

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Thanks mate!

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