What is motor efficiency? As seen below:

Well the technical answer is the mechanical work output divided by the electrical power input, due to friction losses and internal resistances and lots of other things, the mechanical work out is always less.

Belts have high efficiency (90-98%, usually 95%). I prefer to use 92% for my calculations.

but for accurate speed calc you need to account for road friction, wind, rider weight, imperfect alignmentâ€¦

based on the various setups iâ€™ve tried by swapping motors/batteries/wheels/drive ratios and comparing with predicted results aka science, 70 - 80% is the way to go for single drivesâ€¦ 92% is optimisticâ€¦and just crazy if you were selling based on thatâ€¦

I said 92% just for the belts, not for the whole setup. Of course you need to count in many other variables.

and this is why i added some more variables, dont want newbies to think hubs are 100% efficient because they have no belts. lol

Have you messured the efficiency of a system with dual motors?, I wonder if the efficiency will be the same as in single setups.

I donâ€™t get thisâ€¦ is this an equation?

Yes it is. Itâ€™s a fairly well known one in mechanic engineering in terms of motor or electrical/mechanical efficiency

Can you repeat the equation in a mathematical terms equation? Like x/y=z

I have only ran single. dual should be more efficient, especially for heavy riders (iâ€™m only about 160lb). but can be geared for higher speed instead. in the end gearing is the biggest factor.

Can you repeat the equation in a mathematical terms equation? Like x/y=z

There is actually not much of an equation for mechanical efficiency as it is unitless, times 100%to get a percentage ME=(Mechanical Work Output) /(electric energy entered) *100%

Efficiency = (mechanical work out , Watts) / (electrical work in, Watts)

That would give you an efficiency over 100%. You will be putting in more electrical work to get less mechanical work out.

Yes, youâ€™re a right itâ€™s the inverse of what I wrote. Let me update that.

So what is the true equation then?

What me and @JuniorPotato93 wrote,

Since you have watt divided by watt, it becomes unitless, so basically it becomes a ratio of comparison of what is less efficient to what is 100% efficient if the motor output exactly what was inputted. The best way to use this formula would be through experimental data of inputting a certain amount of energy/power from the battery and measuring on a dynamo type machine what the output is.

Basically it wonâ€™t be 100% or even close to 95-96% if we consider air resistance frictional yadayadayadaâ€¦ So far the only thing even close to 100% efficiency would be a resistance heater used to heat homes. Which come close to 99-99.99%

Hey Newbie If you look at my spread sheet I made, the equation for efficiency in that is correct but it is also theoretical. Real motor efficiency depends on many different factors. This is still a questions that I have not answered very well in the spread sheet yet.
E% = (Pout / Pin) *100 or E% = Wout / Win
Ex. 800/1000=.8 -> .8*100 = 80% efficient
Pout = Ď„ * Ď‰
Pin = I * V
so
if 100% efficiency Pout = Pin or Ď„ * Ď‰ = I * V

Pout â€“ output power, measured in watts (W); Pin â€“ input power, measured in watts (W); I â€“ current, measured in amperes (A); V â€“ applied voltage, measured in volts (V). Ď„ â€“ torque, measured in Newton meters (Nâ€˘m); Ď‰ â€“ angular speed, measured in radians per second (rad/s). Resource: Simple Motor Calculations Let me Know if you have any more questions.