9s? You mean 12s? 6-10s is absolutely fine. 10s is optimal for VESC. 12s is where you should stop. I use 13s due to technical reasons and I occasionally get VESC shut-off’s regen-breaking when battery is fully charged.
He’s on 9s now @MannyM0E 9s is completely fine, I used 9s for months cause that was the most I could fit, it’s only a couple mph diff at the top end compared to 10s
You’re missing the meaning of “pushing the limit”
You havent exceeded the limits of a 10s4p for instance, you’re not exceeding anything by just having a 13s battery plugged in 
10s4p 30q gets you almost 3kw…so…
8s4p gets you 2.3kw
Like I said youre not exceeding the limits of lower voltages…so how does going higher make sense
@ZackoryCramer I’m all for pursuing and exceeding limits(safely) but does getting a Ferrari to go faster than a Honda Civic when you’ve only gone 20mph in the Honda make sense?
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What motor are you using? Also, I think the limit of your power comes from having only 2 in parallel, the battery can only deliver about 40 Amps in that config. If you want 2+ kw, the safer thing to do would be to run 12s4p or even 12s6p and it’ll get you there.
Yes, that’s why I said I am planning on using 13s4p, an upgrade from 13s2p. I am using a TB 6374 190kv geared at 20/36.
Why do you have it geared so high? That’s set to a top speed of like 45 mph. Have you ever hit that?
I don’t think a 6374 really has enough power on its own to hit 45 mph in a reasonable scenario.
You said 13s 
And yeah wack gearing, that’s why you’re not maxing out wattage
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My max wattage with 2p is 1.6kw. I wanted to reach more than 2kw(pushing the 2p limit) which could be done with 4p. And why would a high gearing not max out wattage. Ive never gone more than 30mph.
Exactly, youre geared for speed but not using it, thus not maxing wattage
Isn’t the faster you go the more power you’re drawing. And don’t I reach max battery power output when the motor can’t reach its full potential?
Fast acceleration= higher wattage You can achieve high speed using low wattage
Faster speed by physics mean higher wattage. P=F*V^2 When you said you can achieve high speed with “low wattage”, what is that relative to? Couldn’t be that of the lower speeds. 
I think you’re forgetting about torque
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Woah woah woah… I just finished ap mechanics with a 5. Don’t get me started on torque. If u no what I mean 
Damn how skinny are you
I think he Said he Weighs 50kg and but-boards all the time so he does not fly off like a kite,
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i find it hard to believe that you’re ready to push the limits if you can’t even figure out how to stand on your board…
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Seriously though, power is (f x d)/t, so in this case that’s τθ/t, so if you have really small torque your wattage can still be really low on a high speed system if you accelerate slowly
Okay, there’s 2 things you need to consider. First is the power output to the motor. Second is the power output at the wheels. Power through the motor is determined strictly through wattage. I’m assuming by you saying that you want more “power” in your board, you want faster acceleration and better hill climbing. This is dependent on torque, this is the rotational force to get your wheels moving. More torque is better acceleration and hill climbing.
By having it geared so high, you are sacrificing torque for high top speed, but if you aren’t riding anywhere near that top speed, (and I don’t think its even possible to hit 45 mph with 1 6374), then you’re basically not using the only reason someone would have to put a larger pulley on the motor. Basically you’re not using the power the motor is putting out to its full extent.
Try swapping the 20T motor pulley for a 13T or 15T (depending on top speed preferences), and see what happens. I guarantee it’ll feel like a completely different board.